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      NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1

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      • NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1

      NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1

      Get Free NCERT Solutions for Class 10 Maths Chapter 8 Ex 8.1 Introduction to Trigonometry Class 10 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 8.1 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 8 Maths Class 10 Introduction to Trigonometry Exercise 8.1 Provided in NCERT Textbook.

      Topics and Sub Topics in Class 10 Maths Chapter 8 Introduction to Trigonometry:

      Section Name Topic Name
      8 Introduction to Trigonometry
      8.1 Introduction
      8.2 Trigonometric Ratios
      8.3 Trigonometric Ratios Of Some Specific Angles
      8.4 Trigonometric Ratios Of Complementary Angles
      8.5 Trigonometric Identities
      8.6 Summary

       

      NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1

      NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1.

      Board CBSE
      Textbook NCERT
      Class Class 10
      Subject Maths
      Chapter Chapter 8
      Chapter Name Introduction to Trigonometry
      Exercise Ex 8.1
      Number of Questions Solved 11
      Category NCERT Solutions

      Ex 8.1 Class 10 Maths Question 1.
      In ∆ABC right angled at B, AB = 24 cm, BC = 7 cm. Determine:
      (i) sin A, cos A
      (ii) sin C, cos C
      Solution:
      NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.1 Q1

      Ex 8.1 Class 10 Maths Question 2.
      In given figure, find tan P – cot R.
      Solution:
      NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.1 PDF Download Q2

      You can also download the free PDF of Chapter 8 Ex 8.1 Introduction to Trigonometry NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

      Download NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry PDF

      Ex 8.1 Class 10 Maths Question 3.
      If sin A = 34 , calculate cos A and tan A.
      Solution:
      NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.1 PDF Q3

      Ex 8.1 Class 10 Maths Question 4.
      Given 15 cot A = 8, find sin A and sec A.
      Solution:
      NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.1 Free PDF Download Q4

      Ex 8.1 Class 10 Maths Question 5.
      Given sec θ = 1312 , calculate all other trigonometric ratios.
      Solution:
      NCERT Solutions for Class 10 Maths Chapter 8 Trigonometry Exercise 8.1 Q5

      Ex 8.1 Class 10 Maths Question 6.
      If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.
      Solution:
      Exercise 8.1 Class 10 NCERT Solutions Chapter 8 Trigonometry Q6

      Ex 8.1 Class 10 Maths Question 7.
      If cot θ = 78, evaluate:
      (i) (1+sinθ)(1−sinθ)(1+cosθ)(1−cosθ)
      (ii) cot²θ
      Solution:
      Exercise 8.1 Class 10 NCERT Solutions Chapter 8 Trigonometry Free PDF Download Q7

      Ex 8.1 Class 10 Maths Question 8.
      If 3 cot A = 4, check whether 1−tan2A1+tan2A = cos² A – sin² A or not.
      Solution:
      Exercise 8.1 Class 10 NCERT Solutions Chapter 8 Trigonometry Free PDF Download Q7

      Ex 8.1 Class 10 Maths Question 9.
      In triangle ABC, right angled at B, if tan A = 1√3, find the value of:
      (i) sin A cos C + cos A sin C
      (ii) cos A cos C – sin A sin C
      Solution:
      Trigonometry Class 10 Chapter 8 Exercise 8.1 NCERT Solutions Free PDF Download Q9
      Trigonometry Class 10 Chapter 8 Exercise 8.1 NCERT Solutions PDF Q9.1

      Ex 8.1 Class 10 Maths Question 10.
      In ΔPQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.
      Solution:
      Trigonometry Class 10 Chapter 8 Exercise 8.1 NCERT Solutions Q10

      Ex 8.1 Class 10 Maths Question 11.
      State whether the following statements are true or false. Justify your answer.
      (i) The value of tan A is always less than 1.
      (ii) sec A = 125 for some value of angle A.
      (iii) cos A is the abbreviation used for the cosecant of angle A.
      (iv) cot A is the product of cot and A.
      (v) sin θ = 43 for some angle.
      Solution:
      Trigonometry Class 10 Chapter 8 Exercise 8.1 NCERT Solutions PDF Download Q11

      Class 10 Maths Introduction To Trigonometry

      Trigonometry

      Trigonometry is the study of relationships between the sides and angles of a right-angled triangle.

      Trigonometric Ratios

      Trigonometric ratios of an acute angle in a right triangle express the relationship between the angle and the length of its sides.
      Let ∆ABC be a triangle right angled at B. Then the trigonometric ratios of the angle A in right ∆ABC are defined as follows:
      NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 Q11

      NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 Q11.1

      Note:
      The values of the trigonometric ratios of an angle do not vary with the lengths of the sides of the triangle, if the angle remains same.
      NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 Q11.2

      Trigonometric Ratios for Complementary Angles

      sin (90° – A) = cos A
      cos (90° – A) = sin A
      tan (90° – A) = cot A
      cot (90° – A) = tan A
      sec (90° – A) = cosec A
      cosec (90° – A) = sec A
      Note:
      Here (90° – A) is the complementary angle of A.

      Trigonometric Identities

      An equation involving trigonometric ratios of an angle is called a trigonometric identity, if it is true for all values of the angle(s) involved.
      (i) sin2θ + cos2θ = 1 [for 0° ≤ θ ≤ 90°]
      (ii) sec2θ – tan2θ = 1 [for 0° ≤ θ ≤ 90°]
      (iii) cosec2θ – cot2θ = 1 [for 0° < θ ≤ 90°]

      NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry (Hindi Medium) Ex 8.1

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