Show that any positive odd integer of the form 6q+ 1 or 6Q + 3 or 6Q + 5 were q in some integer
Solution
Let a be any positive odd integer and b = 6.
We can apply Euclid’s division algorithm on a and b = 6.
⇒a=6q+r
We know that value of b = 6.
⇒0≤r<6
∴ All possible values of a are:
a = 6q
a = 6q+1
a = 6q+2
a = 6q+3
a = 6q+4
a = 6q+5
Here 6q, 6q+2 and 6q+4 are divisible by 2 since 2 is factor of them.
⇒ They are not positive odd integers.
∴ 6q+1, 6q+3 and 6q+5 are positive odd integers.
∴ Any positive odd integer is of the form (6q+1) or (6q+3) or (6q+5).