Gujarat Board Statistics Class 12 GSEB Solutions Part 2 Chapter 5 Differentiation Ex 5.1 Textbook Exercise Questions and Answers.

Gujarat Board Textbook Solutions Class 12 Statistics Part 2 Chapter 5 Differentiation Ex 5.1

Obtain the derivatives of the following functions with the help of definition:

Question 1.
f(x) = 2x + 3
Solution:
Here, f(x) = 2x + 3
∴ f(x + h) = 2 (x + h) + 3 = 2x + 2h + 3

Hence, f(x) = 2x + 3 then f’(x) = 2.

f(x) = x²
Solution:
Here, f(x) = x²
∴ f(x + h) = (x + h)² = x² + 2xh + h²

Hence, f(x) = x² then f'(x) = 2x.

Question 3.
f(x) = x⁷
Solution:
Here, f(x) = x⁷
∴ f(x + h) = (x + h)⁷

Take, x + h = t, when h → 0, t → x and h = t – x

Hence, f(x) = x⁷ then f'(x) = 7x⁶

Question 4.
f(x) = (frac{1}{x+1}), x ≠ -1
Solution:
Here, f(x) = (frac{1}{x+1})
∴ f(x + h) = f(x)

Hence, f(x) = (frac{1}{x+1}) then f'(x) = (-frac{1}{(x+1)^{2}}).

Question 5.
f(x) = (sqrt[3]{x})
solution:
Here, f(x) = (sqrt[3]{x}=x^{frac{1}{3}})

∴ f(x + h) = ((x+h)^{frac{1}{3}})

Take, x + h = t, when h → 0, t → x and h = t – x

Hence, f(x) = (sqrt[3]{x}) then f'(x) = (frac{1}{3 cdot x^{frac{2}{3}}}).

Question 6.
f(x) = 24, x ≠ (frac{4}{3})
Solution:
Here, f(x) = (frac{2}{3 x-4})

∴ f(x + h) = (frac{2}{3(x+h)-4})

Hence, f(x) = (frac{2}{3(x+h)-4}) then f’(x) = (frac{-6}{(3 x-4)^{2}}).

Question 7.
f(x) = 10
Solution:
Here, f(x) = 10
∴ f(x + h) = 10

Hence, f(x) = 10 then f’(x) = 0